Question

change in magnetic flux linked with a coil is 6 wb. if resistance of the coil is 2 ohm, then charge flow through the wire is​

Answer 1

Answer:

• The Charge flow (q) is 3 Coulombs

Explanation:

The change in magnetic flux of coil is 6 wb i.e. ΔΦ = 6 wb, and the resistance of coil is 2Ω,  we need to find the charge flowing through wire is.

So, From the formula we know that,

⇒ V = ΔФ/Δt

Substituting the values,

⇒ V = 6/Δt

⇒ V = 6/t  ____[1]

Now,We know that,

⇒ Q = I.t

Solving,

⇒ Q = (V/R) × t              ∵ (I = V/R)

⇒ Q = 6/t × t/R

⇒ Q = 6/R

⇒ Q = 6/2

⇒ Q = 3 Coulombs

∴ The Charge flow (q) through the wire is 3 Coulombs.

Answer 2

Given : Change in magnetic flux linked with a coil is 6 wb.

             Resistance of the coil is 2 ohm.

To Find : Charge flow through the wire

Solution :

The change in magnetic flux of coil is 6 wb

ΔΦ = 6 wb,

Resistance of coil is 2Ω,  

From the formula  

 V = ΔФ/Δt

Substituting the values,

 V = $\[\frac{6}{{\Delta t}}\]$

 V = $\[\frac{6}{t}\]$

As, charge flow through the wire

Q = I.t

 Q = (V/R) × t                                           ∵ (I = V/R)

 Q = $\[\frac{6}{t} \times \frac{t}{R}\]$

 Q = 6/R C                                               ( R = 2 ohm)

Q = 6/2 C

 Q = 3 Coulombs

Hence, charge flow through the wire is 3 Coulombs.