Question

Change in oxidation state for KMnO, in acid
medium, neutral and strong alkali
respectively​

Answer 1

Answer:

Equation for reduction of KMnO4 in acidic medium:

8H(+) + MnO4(2-) + 5e(-) ----------> Mn(2+) + 4H2O

In neutral medium:

2H2O + MnO4(-) + 3e(-) ------------> MnO2 + 4OH(-)

In basic medium:

MnO4(-) + e(-) ------------> MnO4(2-)

Thus, you can see that oxidizing effect of KMnO4 is maximum in acidic medium and least in basic medium as in acidic medium the reduction in oxidation state of Mn is max while it is the least in basic medium.

Hence, acidic medium is used when you want strong oxidization and basic when very mild oxidization is required.