Question

Change in the internal energy when 4kj of work is done on the system and 1kj of heat is given out by the system is

Answer 1

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Answer 2

Answer:

$\Delta U=+3\ kJ$

Explanation:

It is given that,

Work done by the system, W = +4 kJ

Heat given out of the system, Q = -1 kJ

Let $\Delta U$ is the change in the internal energy of the system. It can be calculated using the first law of thermodynamics as :

$\Delta U=Q+W$

$\Delta U=-1\ kJ+4\ kJ$

$\Delta U=+3\ kJ$

So, the change in the internal energy of the system is 3 kJ. Hence, this is the required solution.