Question

change in velocity of a body is 5 times that of the initial velocity find the final kinetic energy of the body​

Answer 1

Explanation:

Initial velocity =v; Final velocity =3v

Initial kinetic energy k1=21×m×v2

Final kinetic energy k2=21×m×(3v)2=91×21mv2

Change in kinetic energy =21mv2−91×21mv2

=21mv2(1−91)

=98×21×mv2

=98× Initial kinetic energy.

Answer 2

Explanation

Explanation:

Explanation:Initial velocity =v; Final velocity =3v

Explanation:Initial velocity =v; Final velocity =3vInitial kinetic energy k1=21×m×v2

Explanation:Initial velocity =v; Final velocity =3vInitial kinetic energy k1=21×m×v2Final kinetic energy k2=21×m×(3v)2=91×21mv2

Explanation:Initial velocity =v; Final velocity =3vInitial kinetic energy k1=21×m×v2Final kinetic energy k2=21×m×(3v)2=91×21mv2Change in kinetic energy =21mv2−91×21mv2

Explanation:Initial velocity =v; Final velocity =3vInitial kinetic energy k1=21×m×v2Final kinetic energy k2=21×m×(3v)2=91×21mv2Change in kinetic energy =21mv2−91×21mv2=21mv2(1−91)

Explanation:Initial velocity =v; Final velocity =3vInitial kinetic energy k1=21×m×v2Final kinetic energy k2=21×m×(3v)2=91×21mv2Change in kinetic energy =21mv2−91×21mv2=21mv2(1−91)=98×21×mv2

Explanation:Initial velocity =v; Final velocity =3vInitial kinetic energy k1=21×m×v2Final kinetic energy k2=21×m×(3v)2=91×21mv2Change in kinetic energy =21mv2−91×21mv2=21mv2(1−91)=98×21×mv2=98× Initial kinetic energy.