Question

Change in volume when 100 ml N2H4(g) decomposes into N2(g) and H2(g) is?
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Answer 1

Answer:

Let the initial mixture contains n

1

& n

2

moles of NH

3

& N

2

H

4

respectively.

Total moles of gases originally present =n

1

+n

2

.

Total moles of gases after decomposition of gases =2n

1

+3n

2

.

Now, using ideal gas law: PV=nRT

0.5×V=(n

1

+n

2

)R×300........(i)

4.5×V=(2n

1

+3n

2

)R×1200........(ii)

Solving these two equations, we get-

n

1

+n

2

2n

1

+3n

2

=

4

9

=>

n

2

n

1

=

1

3

Answer 2

Answer:

it decreases by 100 ml

Explanation:

i hope u understand