{Change into indirect speech}
The policeman said to the thief, “ I have caught you now red handed and cannot
allow you to go unless you confess all your previous crimes. ”
please answer this question.
Answers
Answer:
Answer:−
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\sf \red {Given:-}Given:−
▸No of divisions,the circular head of the screw gauge is divided = 20
▸Distance moved =1mm
▸Number of rotations=2
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\sf \blue {To\: Find:-}ToFind:−
▸Least count of the screw gauge=?
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\sf \pink {We\: Know:-}WeKnow:−
\bf \mapsto {Least\: Count=\frac{pitch}{No.\: of\: divisions}}↦LeastCount=
No.ofdivisions
pitch
▸Inorder to calculate the least count,pitch is to be determined.
▸To determine pitch we have a formula,
\bf \mapsto {Pitch=\frac{Distance\: moved}{No.\: of\: rotations}}↦Pitch=
No.ofrotations
Distancemoved
\bf \mapsto {Pitch=\frac{1mm}{2}}↦Pitch=
2
1mm
\bf \implies \green {Pitch=0.5mm}⟹Pitch=0.5mm
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\sf \orange {Now,}Now,
\bf \mapsto {Least\: Count=\frac{pitch}{No.\: of\: divisions}}↦LeastCount=
No.ofdivisions
pitch
\bf \mapsto {Least\: Count=\frac{0.5mm}{20}}↦LeastCount=
20
0.5mm
\bf \mapsto {Least\: Count=\frac{5mm}{20\times10}}↦LeastCount=
20×10
5mm
\bf \mapsto {Least\: Count=\frac{5mm}{200}}↦LeastCount=
200
5mm
\bf \mapsto {Least\: Count=\frac{\cancel{5}^{1}mm}{\cancel{200}_{40}}}↦LeastCount=
200
40
5
1
mm
\bf \mapsto {Least\: Count=\frac{1mm}{40}}↦LeastCount=
40
1mm
\bf \implies \green {\fbox{Least\: Count=0.025mm}}⟹
LeastCount=0.025mm
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\sf \purple {Thence,}Thence,
▸The least count of the screw gauge is 0.025mm.