change the narration Ram said I need help with my homework
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0
Answer:
Answer:
17/√7 is the 15th term of AP
Step-by-step explanation:
let an= 17/√7
a=3/√7
d=a2-a1
= 4/√7-3/√7
=1/√7
an= a+(n-1)d
\frac{17}{ \sqrt{7} } = \frac{3}{ \sqrt{7} } + (n - 1) \times \frac{1}{ \sqrt{7} }
7
17
=
7
3
+(n−1)×
7
1
\frac{17}{ \sqrt{7} } = \frac{3}{ \sqrt{7} } + \frac{n}{ \sqrt{7} } - \frac{1}{ \sqrt{7} }
7
17
=
7
3
+
7
n
−
7
1
\frac{17}{ \sqrt{7} } = \frac{2}{ \sqrt{7} } + \frac{n}{ \sqrt{7} }
7
17
=
7
2
+
7
n
\frac{17}{ \sqrt{7} } - \frac{2}{ \sqrt{7} } = \frac{n}{7}
7
17
−
7
2
=
7
n
\frac{15}{ \sqrt{7} } = \frac{n}{ \sqrt{7} }
7
15
=
7
n
\frac{15}{ \sqrt{7} } \times \sqrt{7} = n
7
15
×
7
=n
n = 15n=15
✓✓Hope it helps✓✓
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Answer:
Ram said that he needed help with his homework
i hope it's helpful
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