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Answers

Answered by Anonymous
0

Answer:

Given three charges 5nC, 10nC and −5nC placed at corners A, B and C of square ABCD of side 2m.  

To find the work done in transferring 5μC from D to point of intersection of diagonals.

AC=BD=  

(2)  

2

+(2)  

2

 

=  

4+4

=2  

2

=2.28m

AO=BO=CO=  

2

2.828

=1.414m

Potential at O, V  

O

=  

4πε  

0

 

1

[  

AO

q  

1

 

+  

BO

q  

2

 

+  

CO

q  

3

 

]

Potential at D, V  

D

=  

4πε  

0

 

1

[  

AD

q  

1

 

+  

BD

q  

2

 

+  

CD

q  

3

 

]

W= work done =q[V  

O

−V  

D

]

Here, q=5μC

So, W=5×10  

−6

×9×10  

9

×[5×10  

−9

[  

AO

1

−  

AD

1

]+10×10  

−9

[  

BO

1

−  

BD

1

]−5×10  

−9

[  

CO

1

−  

CD

1

]]

=45×10  

−6

×10  

9

×10  

−9

[5×(  

1.414

1

−  

2

1

)+10×(  

1.414

1

−  

2.828

1

)−5×(  

1.414

1

−  

2

1

)]

=450×10  

−6

×(  

1.414

1

−  

2.828

1

)

=  

1.414

450×10  

−6

 

(1−  

2

1

)=159.12×10  

−6

 Joules

Explanation:

Answered by rawatnikita65
0

Answer:

ok

Explanation:

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