Question

chapater linear equations in one variable word problem Q6​

Answer 1

Answer:

Let the numbers are 3x and 5x

increased by 5 then

(3x+5)/(5x+5)=2/3

3(3x+5)=2(5x+5)

9x+15=10x+10

5=x

x=5

original numbers are 3*5 =15 & 5*5=25

hope it helps

Answer 2

Question:-

Two numbers are such that the ratio between them is 3 : 5. If each is increased by 5, the ratio between the new numbers so formed is 2 : 3. Find the original numbers.

Answer:-

The two numbers are 15 and 25 respectively.

Solution:-

Ratio of two numbers = 3 : 5

Let the first number be 3x

and the second number be 5x

The new numbers when increased by 5,

The first number = 3x + 5

The second number = 5x + 5

Ratio of the new numbers = 2 : 3

According to problem,

$= > \dfrac{3x + 5}{5x + 5} = \dfrac{2}{3}$

Cross multiplying the terms.

$= > 2(5x + 5) = 3(3x + 5)$

$= > 10x + 10 = 9x + 15$

$= > 10x - 9x = 15 - 10$

$= > x = 5$

Hence, the value of x is 5.

Therefore,

The first number => 3 × 5 = 15

The second number => 5 × 5 = 25