chapter 10 of 9 class ex 10 .5 question number 2 no spam with me <br />
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Step-by-step explanation:
In AOAB,
AB OA OB radius
AOAB is an equilateral triangle.
Therefore, each interior angle of this triangle will be of 60°
AOB 60°
ZACH! ZAMOB (60)-30°
In cyclic quadrilateral ACBD,
DACB DADB 180° (Opposite angle in cyclic quadrilateral)
DADB 180° 300 150°
Therefore, angle subtended by this chord at a point on the major arc and the minor
arc are 30° and 150° respectively.
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