Chapter 11 perimeter and area question 11 the deamination of pool are in the ratio 4:3:1 if the volume is 6144 metre cube find the total surface area of the pool
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let ratio be x
then dimensions will be 4x, 3x, x
ATQ V=6144
4x. 3x. x=6144
12x^3=6144
x^3=6144/12
x^3=512
x=8
L =32, b=24, h=8
Total Surface Area= 2(32x24+24x8+8x32)
=2(768+192+256)
=2x1216
2432
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