Question

Chapter 11 science questions no. 1234567

Answer 1

A1: Accommodation

A2: Retina

A3: 25cm

A4: Ciliary muscles

A5: DISTINCT VISION
Power of lens needed for correction distant vision of the person(p)=-5.5D
P=1/f , f=1/P = -1/5.5 = -0.18m = -18cm

NEAR VISION
P= 1.5D
f=1/P = 1/1.5m = 0.67m = 66.7cm

A6: To correct myopia the person concerned should use concave lens of focal length= -80cm = -0.80m
P=1/f = -1/0.80 = -100/80 = -1.25D