Question

Chapter 7
1. prove that the sides opposite to equal angles of a triangle
are equal​

Answer 1

Let us take ∆ABC to be a iscoscles triangle...

Construction :

Draw a Median from A to BC at D... So AD is the median .

Given :

Angle ABD = Angle ACD

Proof :

Consider ∆ABD and ∆ACD,

AD = AD (Common)

Angle ABD = Angle ACD (Given)

BD = CD (Median AD bisects BC)

By SAS Congruency, ∆ABD =~∆ACD

=> By $CPCT$ AB = AC

Hence Proved...

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