Question

chapter-8 excercise-8.1
6 queston- if<A and<B are acute angle such that cos A=B then show <A=<B.

Answer 1

❤❤Here is your answer ✌ ✌

$\huge\underline {\red {\bold {Answer}}}$


I hope it helps you

Answer 2

Given,

∠A  and ∠B  are acute angles  ΔABC as  shown in picture,

Now,

in ΔADC

CosA = AD/AC

in ΔBDC  

CosB = AD/BC  

Given,

CosA = CosB

AD/AC = AD/BC

AC  = BC  

We know that, in  a triangle if  two opposite sides are euqal, there corresponding angles  will be  also equal. Hence,

∠A = ∠B