Question

chapter Algebraic Identities

Please solve the above question
The answer is - 9/4 x² - 33/5 pqx + 8/5 p²q²

I want the solving ​

Answer 1

$\huge \fbox \green{Answer:}$

$\textbf{Given:} \: \left( \frac{3}{4} x - 2pq\right) \] \left(3x - \frac{4}{5}pq \right) \]$

$\textbf{To Do – Find Product}$

$\sf \colorbox{pink} {Now Solve}$

$⇒ \left( \frac{3}{4} x - 2pq\right) \] \left( 3x - \frac{4}{5} pq\right) \]$

$= \frac{9}{4} {x}^{2} - \frac{12}{20} x \: pq - 6x \: pq + \frac{8}{5} {p}^{2} \: {q}^{2}$

$= \frac{9}{4} {x}^{2} - \frac{132}{20} x \: pq + \frac{8}{5} {p}^{2} {q}^{2}$

$\\ \\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$

Answer 2

Step-by-step explanation:

(

4

3

x−2pq)(3x−

5

4

pq)

= \frac{9}{4} {x}^{2} - \frac{12}{20} x \: pq - 6x \: pq + \frac{8}{5} {p}^{2} \: {q}^{2}=

4

9

x

2

−

20

12

xpq−6xpq+

5

8

p

2

q

2

= \frac{9}{4} {x}^{2} - \frac{132}{20} x \: pq + \frac{8}{5} {p}^{2} {q}^{2}=

4

9

x

2

−

20

132

xpq+

5

8

p

2

q

2