Question

Chapter: Arthmetic and geometric progession
Which term of the arithmetic progression 5, 15, 25, ----- will be 130 more than its 31st
term?

Answer 1

Answer:

435

Step-by-step explanation:

1st term = 10 - 5=5

2nd term =20 - 5 =15

3rd term = 30-5 = 25

4th term = 40-5 =35 ..........................

31st term = 310-5 =305

305 + 130 = 435

Answer 2

Answer:

5, 15,25..........

a=5, d=10

31st term =a+30d

=5+30(10)

=5+300

=305

31st term is 305

305+130

=435

let 436 be nth term of AP

an=a+(n-1)d

435=5+(n-1)10

435-5=(n-1)10

430/10=n-1

n-1=43

n=43+1

n=44

there 435 is 44th term of the AP