Question

chapter centre of mass please solve it i will give you whatever you want.....​

Answer 1

Answer:

Solution:

According to law of conservation of linear momentum along x-axis, we get 

m1×0+m2×v=m1v′cosθm1×0+m2×v=

m1v′cosθ 

m2v=m1v′cosθm2v=m1v′cosθ 

or cosθ=m2υm1υ′...(i)cosθ=m2υm1υ′...(i) 

According to law of conservation of linear momentum along y-axis, we get 

m1×0+m2×0=m1υ′sinθ+m2υ2m1×0+m2×0=m1υ′

sinθ+m2υ2

−m2υ2=m1υ′sinθ−m2υ2=m1υ′sinθ 

sinθ=−m2υ2m1υ′sinθ=−m2υ2m1υ′ (ii) 

Divide (ii) by (i), we get 

tanθ=−12tan⁡θ=−12 

or θ=tan−1(−12)θ=tan−1(−12) to the x-axis

Explanation:

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