chapter circle answer plzz
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Given, RS∥PQ and ∠RPQ=30
o
PR=PQ (equal tangents)
∠PRQ=∠PQR (angle opposite to equal sides)
In △PQR
∠PRQ+∠PQR+∠RQP=180
o
2∠PQR+30
o
=180
o
∠PQR=75
o
∠SRQ=∠PQR=75
o
(alternate angle)
Also, ∠RQP=∠RSQ=75
o
(alternate segment angles)
∠RSQ=∠SRQ=75
o
In △QSR
∠RSQ+∠SRQ+∠SQR=180
o
75+75+∠SQR=180
∠SQR=30
o
∠RQS=30
o
Step-by-step explanation:
Answer is righ please write it
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