Question

chapter-direct and inverse variations 1. mr.goswami walks at an average speed of 2.5 km per 45 minutes. find his speed per hour? plz explain me​

Answer 1

Step-by-step explanation:

Let his speed be x.

If 2.5 : 45 :: x : 60, (60 because 1 hour = 60 minutes.)

2.5 ÷ 45 =x ÷ 60,

25 ÷ 450= x ÷ 60,

After cross multiplying,

450x = 25 × 60,

450x = 1500,

x = 1500÷450,

x = 3.333 .

Hope this answer helped in your exam.

Answer 2

Answer:

3Km

Step-by-step explanation:

Distance walked in 45 min= 2.5km

So, Distance walked in 1min = 2.5/45= 0.05km

The distance walked in 1hr = 0.05×60= 3km

Speed in km/hr = 3km/hr

Do let me know If I am wrong.