Question

Chapter:-Exponent

Evaluate

$(6^{ - 1} - 8^{ - 1} )^{ - 1} + (2 ^{ - 1} - 3^{ - 1} )^{ - 1}$
Please give correct answer.

Its urgent fast.​

Answer 1

Answer:

30

Important points :

• if whole power is in negative you can change into positive by reciprocal
• if a single number power is in negative you can change into fraction by 1 as numerator and a that single number as a denominator

I have solved the right answer

Hope it Helps

please my answer as brainliest answer

Answer 2

Step-by-step explanation:

${( {6}^{ - 1} - {8}^{ - 1} )}^{ - 1} + ( { {2}^{ - 1} - {3}^{ - 1}) }^{ - 1} \\ \\ = {( \frac{1}{6} - \frac{1}{8} )}^{ - 1} + ( {\frac{1}{2} - \frac{1}{3}) }^{ - 1} \\ \\ = ({ \frac{4 - 3}{24})}^{ - 1} + ( { \frac{3 - 2}{6}) }^{ - 1} \\ \\ = { (\frac{1}{24}) }^{ - 1} + {( \frac{1}{6}) }^{ - 1} \\ \\ = 24 + 6 \\ \\ = 30 \\ \\ Hope \: it \: helps \: you...... \\ Please \: mark \: my \: answer \: as \: \\ brainleist.....$