Physics, asked by rachnashukla9578, 2 months ago

chapter- gravitation​

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Answered by zk910475
0

Answer:

1:)The orientation of an object's acceleration is given by the orientation of the net force acting on that object. s is the distance covered by the particle from top to bottom of the tower. Therefore, the final velocity of the particle is v=19.6m/sec . ⇒s=ut+12at2 .

2)A freely falling body always experience a downward acceleration g which we call as acceleration due to gravity.

Thus acceleration of freely falling body a=g=9.8 m/s

2

(Taking downward direction to be positive)

Initial speed of that body u=0

Equations of motion :

(i) : v=gt

(ii) : S=

2

1

gt

2

(iii) : v

2

=2gS

Explanation:

hope my answer helps u

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