Chapter :- Gravitation.
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Q.3
Given,
g = 9.8m/s²
h = 40m
initial velocity = 0m/s
From 3rd Eqn
![v {}^{2} - u {}^{2} = 2gh \\ v {}^{2} = u { }^{2} + 2gh \\ v {}^{2} = 0 { }^{2} + 2 \times 9.8 \times 40 \\ v {}^{2} = 2 \times 9.8 \times 40 \\ v { }^{2} = 19.6 \times 40 \\ v {}^{2} = 784 \\ v = \sqrt[]{784} \\ v = 28](https://tex.z-dn.net/?f=v+%7B%7D%5E%7B2%7D++-+u+%7B%7D%5E%7B2%7D++%3D+2gh+%5C%5C+v+%7B%7D%5E%7B2%7D++%3D+u+%7B+%7D%5E%7B2%7D++%2B+2gh+%5C%5C+v+%7B%7D%5E%7B2%7D++%3D+0+%7B+%7D%5E%7B2%7D++%2B+2+%5Ctimes+9.8+%5Ctimes+40+%5C%5C+v+%7B%7D%5E%7B2%7D++%3D+2+%5Ctimes+9.8+%5Ctimes+40+%5C%5C+v+%7B+%7D%5E%7B2%7D++%3D+19.6+%5Ctimes+40+%5C%5C+v+%7B%7D%5E%7B2%7D++%3D+784+%5C%5C+v+%3D++%5Csqrt%5B%5D%7B784%7D+%5C%5C+v+%3D+28 "v {}^{2} - u {}^{2} = 2gh \\ v {}^{2} = u { }^{2} + 2gh \\ v {}^{2} = 0 { }^{2} + 2 \times 9.8 \times 40 \\ v {}^{2} = 2 \times 9.8 \times 40 \\ v { }^{2} = 19.6 \times 40 \\ v {}^{2} = 784 \\ v = \sqrt[]{784} \\ v = 28")
Hence, final velocity = 28m/s.
✌✌✌✌✌
Given,
g = 9.8m/s²
h = 40m
initial velocity = 0m/s
From 3rd Eqn
Hence, final velocity = 28m/s.
✌✌✌✌✌
Thanks a lot. .
:-)
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