Question

Chapter :- Introduction to Trigonometry
Class :- 10th
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REFER TO ATTACHMENT​

Answer 1

(i)

$sinA \: cosC \: + cosA \: sinC \\ = sinA \: cosA \: + cosA \: sinA \\ = 2 \: sinA \: cosA \\ = sin \: (2A)$

(ii)

sin B = sin 90° = 1

cos B = cos 90° = 0

Now,

$sinA \: sinB \: +cosA cosB \\ = sinA \:(1) + cosA \: (0) \\ = sinA \: + 0 = sinA$

Hope It Helps :)

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