Question

CHAPTER → LINEAR EQUATION IN ONE VARIABLE

CLASS → 6TH

BOOK → DR.RAJESH KUMAR THAKUR

SUB→MATHS​

Answer 1

Step-by-step explanation:

$\frac{y}{2} - \frac{1}{2} = \frac{y}{3} + \frac{1}{4}$

$= > \frac{y - 1}{2} = \frac{4y + 3}{12}$

$= > 12(y - 1) = 2(4y + 3)$

$= > 12y - 12 = 8y + 6$

$= > 12y - 8y = 6 + 12$

$= > 4y = 18$

$= > y = \frac{18}{4}$

$= > y = \frac{9}{2}$