Question

chapter linear equations.

Answer 1

({6y+1/2})+1=7y-3/3

({6y+1}/2)=7y-3-1/3

(6y+1)/2=(7y-2)/3

2(7y-2)=3(6y+1)

14y-4=18y+3. (cross multiply)

14y-18y=3+4. (by transposing)

-4y=7

y=7/-4

hope it helps . Mark it the brainliest

Answer 2

$\red{ \huge{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \: QUESTION\: \: \red{\mid}}}}}}}}$

$\underline{ \bold{ \: \: SOLVE \: : \: \: } } \\ \\ \bold{ \frac{6y + 1}{2 } + 1 = \frac{7y - 3}{3} }$



$\red{ \huge{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \: SOLUTION\: \: \red{\mid}}}}}}}}$



$\bold{ \frac{6y + 1}{2} + 1 = \frac{7y - 3}{3} } \\ \\ \underline{\bold{ \: \: \: Taking \: \: LCM \: \: of \: \:lhs \: }} \\ \\ \\ \bold{ \frac{6y + 1 + 2}{2} = \frac{7y - 3}{3} } \\ \\ \bold{ = > \frac{6y + 3}{2} = \frac{7y - 3}{3} } \\ \\ \underline{ \bold{ \: \: By \: \: cross \: \: multiplication \: \: }} \\ \\ \\ \bold{3(6y + 3) = 2(7y - 3)} \\ \\ \bold{ = > 18y + 9 = 14y - 6} \\ \\ \bold{ = > 18y - 14y = - 6 - 9} \\ \\ \bold{ = > 4y = - 15} \\ \\ \bold{ = > y = \boxed{ \bold{\frac{ - 15}{4} }}}$



$\red{ \huge{ \underline{ \overline{ \mid{ \bold{ \purple{ \: \: VERIFICATION \: \: \red{\mid}}}}}}}}$



$\bold{We \: \: \: get \: \: \: \boxed{ \bold{y = - \frac{15}{4} }}}$

$\bold{Putting \: \: the \: \: value \: \: of \: \: \underline{ \: \: y \: } \: \: in \: \: L.H.S. }$

$\bold{L.H.S. = \frac{6y + 1}{2} + 1 } \\ \\ \bold{ = \frac{6( - \frac{15}{4}) + 1 }{2} + 1} \\ \\ \bold{ = \frac{3( - \frac{15}{2}) + 1 }{2} + 1 } \\ \\ \bold{ = \frac{ \frac{ - 45 + 2}{2} }{2} + 1} \\ \\ \bold{ = \frac{ \frac{ - 43}{2} }{2} + 1 } \\ \\ \bold{ = \frac{ - \frac{ 43}{2} + 2}{2} } \\ \\ \bold{ = \frac{ \: \: \frac{ - 43 + 4}{2} \: \: }{2} } \\ \\ \bold{ = \frac{ - \frac{39}{2} }{2} } \\ \\ \bold{ = - \frac{39}{4} }$

$\bold{Putting \: \: the \: \: value \: \: of \: \: \underline{ \: \: y \: } \: \: in \: \: R.H.S.}$

$\bold{R.H.S.= \frac{7y - 3}{3} } \\ \\ \bold{ = \frac{7( - \frac{15}{4} ) - 3}{3 } } \\ \\ \bold{ = \frac{ \frac{ - 105}{4} - 3}{3} } \\ \\ \bold{ = \frac{ \frac{ - 105 - 12}{4} }{3} } \\ \\ \bold{ = \frac{ - \frac{117}{4} \: \: }{3} } \\ \\ \bold{ = - \frac{117}{4} \times \frac{1}{3} } \\ \\ \bold{ = - \frac{39}{4} }$

$\bold{So,} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \underline{\bold{ \: \: \: \: \: L.H.S.= R.H.S. \: \: \: \: \: }}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \underline{ \underline{ \bold{Hence \: \: Verified. \: \: }}}$