Question

Chapter-magnetism and matter​

Answer 1

Answer:

$m \: times \: \frac{2}{\pi}$

Explanation:

From the definition of Magnetic Dipole moment

M = pole strength × distance between poles

In bar magnet let M=m.l

if magent is bent to semicircle

it's circumference equals length of bar magnet

let radius of magnet be 'r'

Then πr = l

r = l/π _______ eq 1

Now magnetic dipole moment of semicircular magnet is,

Let M1 be magnetic dipole moment of semicircular magnet

M1 = m×2r (where 2r is distance between poles )

M1 = m×2(l/π) (From eq 1)

M1 = m× l×2/π

M1 = M×2/π ( M is magnetic dipole moment of bar magnet)

Hence Magnetic Dipole moment of semicircular magnet is M×2/π

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