Question

Chapter name: Lines and angles
​

Answer 1

Answer:

Consider ABC as a right-angled triangle with ∠C=90∘

We know that the sum of all the angles in a triangle is 180∘.

So we can write it as

∠A+∠B+∠C=180∘

We can write it as

∠A+∠B=180∘−∠C

By substituting the values

∠A+∠B=180∘−90∘

By subtraction

∠A+∠B=90∘

Let us consider ∠A=53∘

By substituting the value of ∠A in ∠A+∠B=90∘

We get

53∘+∠B=90∘

On further calculation

∠B=90∘−53∘

By subtraction

∠B=37∘

Therefore, ∠A=53∘,∠37∘ and ∠C=90∘.

please mark me as brainliest and tq my answer

Answer 2

*Question:-

In a right angled triangle one of the acute angles measures 53°. Find the measure of each angle of the triangle .

*Answer:-

Consider ABC as a right-angled triangle with ∠C = 90°

We know that the sum of all the angles in a triangle is 180°

So we can write it as:-

• ∠A + ∠B + ∠C = 180°

We can write it as :-

• ∠A + ∠B = 180° – ∠C

By substituting the values :-

• ∠A + ∠B = 180° – 90°

By subtraction :-

• ∠A + ∠B = 90°

Let us consider :-

• ∠A = 53°

By substituting the value of ∠A in

∠A + ∠B = 90°

We get :-

• 53° + ∠B = 90°

On further calculation:-

• ∠B = 90° – 53°

By subtraction:-

• ∠B = 37°

Therefore,

• ∠A = 53°,
• ∠B = 37°,
• ∠C = 90°.

$Hope \: it \: helps \: you$