Question

Chapter :- PERCENT AND PERCENTAGE
Question (a) :- In an election , a candidate secured 58% of the votes polled and won the election by 18,336 votes. Find the total number of votes polled and the votes secured by each candidate

Question (b) :- In an election , a candidate secured 47% of votes polled and lost the election by 12,336 votes. Find the total votes polled and the votes secured by the winning candidate

Answer 1

a)

Since, winning candidate secured 58% of the votes polled.

∴ losing candidate secured

= (100 – 58) % of the votes polled

= 42% of the votes polled

Difference of votes = 58 – 42

= 16% of the votes polled

We are given :

16 % of votes polled = 18, 336

⇒ 16/100 of votes polled = 18,336

⇒ Votes polled = 18,336 × 100/16

⇒ votes polled = 18, 33, 600/16

⇒ Votes polled = 1, 14, 600

∴ Votes secured by winning candidate

= 58/100 × 1, 14, 600

= 66, 468

Votes secured by losing candidate

= 42/100 × 1, 14,600

= 48, 132

Votes polled = 1, 14, 600

Votes secured by winning candidate = 66, 468

Votes secured by losing candidate = 48, 132

b)

ANSWER

Let the total number of votes polled be x

No.of votes secured by loosing Candidate =47% of x

No.of votes secured by winning Candidate =53% of x

Given that 53% of x−47% of x=12366

⇒(53−47)% of x=12366

⇒6% of x=12366

⇒

100

6x

=12366

⇒x=206100

Therefore the Total number of vote polled =2,06,100

No.of votes secured by winning Candidate =53% of x

=

100

53

×206100

=109233