Chapter- Probability [ICSE CLASS X]
3,4,5 question.
Answers
3(a) Given,
Probability of winning Ram is 0.48
(i) Probability of not winning ram = (1-probability of winning Ram)
= 1-0.48
Probability of winning Ram = 0.52
(ii) Since there are only two participants.
Therefore,
Probability of winning Shyam = probability of not winning Ram =0.52
3(b) Given,
No. of total bulbs = 600
Defective bulbs = 12
Non-Defective bulbs = 600-12
=588
So,
Probability of taking out non- defective bulb= No. of non-defective bulbs/total bulbs
=588/600.
Coming to next question;
4(a) given,
Two dices are thrown simultaneously
So,
Total possible outcome = 6*6 = 36
(i) The first dice shows 5
Favorable outcomes are
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6) = 6
Probability will be = favorable/ total
= 6/36
= 1/6.
(ii) Both the dices shows same number.
Favorable outcomes are
(1,1),(2,2),(3,3),(4,4),(5,5),(6,6) = 6
Probability will be = favorable/ total
= 6/36
= 1/6.
(iii) The sum of number on the dice is 8
Favorable outcomes are
(1,7),(2,6),(3,5),(4,4),(5,3),(6,2)=6
Probability will be = favorable/ total
= 6/36
= 1/6.
(iv) the product of the numbers on the dice is 8
Favorable outcomes are
(1,8),(2,4),(4,2),(8,1) = 4
Probability will be = favorable/ total
= 4/36
= 1/9.
(v) The total number on the dice is grater than 9
Favorable outcomes are
(6,6),(6,5),(5,6),(5,5)= 4
Probability will be = favorable/ total
= 4/36
= 1/9.
Now come to next one!!!
5(a);- two coins are tossed once.
Total possible outcome are (H,T),(T,H),(H,H),(T,T) = 4
(i) Both tails
Favorable outcome is only one ;- (T,T)
Probability will be = favorable/ total
= 1/4.
(ii) Atleast one head
Favorable outcomes are
(H,T),(T,H),(H,H)= 3
Probability will be = favorable/ total
= 3/4.
(iii) Both head or both tail
Similarly to first one
Probability of getting both head =1/4
Probability of getting both tail =1/4
Probability of getting both head or both tail = ¼ + ¼ = 2/4= ¼
5(b) Total no. of cards = 52
Total no. of face cards =12
Probability of drawing a face card =12/52= 3/13.