Question

» Chapter : PROPERTIES OF MATTER

Solve question no. 48 {refer the attachment} with clear explanation along with steps.
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Answer 1

Given:-

$\bigstar$Distance separated on two knife - edges is 0.6 m

$\bigstar$Cylindrical beam length is 1m

$\bigstar$Mass of the load is 7.3 Kg

$\bigstar$Elevation of the centre is 4.75 × 10-³m

$\bigstar$radius of the beam is 7 × 10-³ m

$\bigstar$We know that g is 9.8 m/s²

To Find:-

$\bigstar$Young' modulus of the beam

Solution:-

$\bigstar$Formula Used ,

$\\ {\underline{ \boxed{ \boxed{ \sf{e \: = \frac{mgal {}^{2} }{2bd {}^{3y} } \times nm { }^{ - 2} }}}}}$

$\bigstar$Substitute the value in formula.

$\\ = \sf \: \frac{3 \times 7.3 \times 9.8 \times 20 \times 0.6 \times 0.6}{2 \times 0.02 \times (14 \times 10 {}^{ - 3} ) {}^{3} \times 4.75 \times 10 {}^{ - 3} }$

$\\ = \sf \: \frac{4292.4 \times 0.36}{0.19 \times 2744 \times 10 {}^{ - 9}{ \times 10 {}^{ - 3} } }$

$\\ = \sf \: \frac{1545.26}{521.36 \times {10}^{ - 2} }$

$\\ { \underline{ \boxed{ \boxed{\sf {\: = \: 2.96 \times {10}^{2} }}}}}$

$\bigstar$The Young's modulus of the beam is 2.96×10²

Answer 2

Answer:

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Given:-

Distance separated on two knife - edges is 0.6 m.

Cylindrical beam

Mass of load is 7.3 kg

Elevation of the centre is 4.75 x 10-³m

radius of the beam is 7 x 10-³

We known that g is 9.8 m/s²

To find:-

Young's modulus of the beam

Solution:-

formula used,

e mgal²/ 2bd³y x nm -2

Substitute the value in formula.

= 3 x 7.3 x 9.8 x 20 x 0.6 x 0.6

2 x 0.02 x (14x10-³)³ x 4.75 x 10-³

= 4292.4 x 0.36

= 0.19 x 2744 x 10-9 x 10-³

= 1545.26

= 521.36 x 10-²

= 2.96 x 10²

The young's modulus of the beam is 2.96 x 10²

Explanation:

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