Question

(chapter.similarity) base of a triangle is 9 and height is 5. base of another triangle is 10 anf height is 6. find the ratio of areas of these triangles​

Answer 1

The ratio of areas of the triangles is

Explanation:

We know that,

For any kind of triangle_

Area = 1/2 ×(base×height)

Case-1:

Base = 9

Height = 5

Hence,

Area = 1/2× base×height

        = 1/2×(9×5)

        =(45/2)

       = 22.5

∴ The area is 22.5   .

Case-2:

Base = 10

Height = 6

∴ Area = 1/2×base×height

           = 1/2×(10×6)

           = (60/2)

           = 30

∴ The area is 30.

∴ The ratio of the areas of triangles is_

22.5 : 30

= 225 : 300 [∵ Ratio never can be in point so multiplying both the sides by 10]

= 225/300

= 9/12 [∵Dividing both the sides by 25.]

= 3/4 [∵ Dividing both the sides by 3.]

= 3:4

Hence, the ratio is 3:4.

#answerwithquality

#BAL

Answer 2

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4