Question

Chapter- Special products and factorization

Q. USING SPECIAL PRODUCT CALCULATE EACH....

1. 101 x 101
2. 68 x 72

Explain fast
step by step. .​

Answer 1

Answer:

Step-by-step explanation:

1. 101 * 101

(100+1)(100+1)

• $(\alpha + \beta)^{2} = \alpha^{2} + 2ab + \beta^{2}$

• (100 + 1) ^ 2 = (100)^2 + 2(100)(1) + 1^2
•                    = 10000 + 200 + 1
•                    = 10201

2. 68 * 72

(70-2)(70+2)

• $(\alpha -\beta )(\alpha +\beta ) = \alpha^{2} - \beta^{2}$
• (70-2)(70+2) = 70 ^2 - 2^ 2
•                     = 4900 - 4
•                     = 4896

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