Math, asked by cfloss, 1 year ago

chapter=Theory of quadratic equations

QUESTION=The sum of the square of two digits of a positive integral number is 65 and the number is 9 times the sum of its digits.Find the number.

Answers

Answered by bharat9291
2
x ^ 2 + y ^ 2 = 65 ........eq 1
9(x + y ) = 10x + y
9y + 9 x = 10x + y
8 y = x
put the value of x in eq 1
( 8y) ^2 + y ^ 2 = 65
64 y ^2 + y ^2 = 65
65 y ^ 2 = 65
y^ 2 = 1
y = 1,-1
neglecting = -1
and by keeping the value of y in eq 1 we get x = 8
so the number is 81

bharat9291: i hope you got it
cfloss: Thank you soo much..but i have a confusion that in the 2nd line where did that 10x came from?
bharat9291: to write a two digit number in expanded form we use this
bharat9291: 50 is written as 5*10 +6*1
bharat9291: so x is at 10s place so i muktiply it by 10
bharat9291: now got it ?
cfloss: yeah i got it..Thank you soo much
bharat9291: welcome .you can ask if you have any other queries
cfloss: ok :) <3
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