Question

chapter5
exercise5.1 question1 part2

plz help me with this question. ​

Answer 1

when 1/4 of the air is removed , then the

remaining air = 1 - 1/4 = 4-1/4 = 3/4

hope it helps you

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Answer 2

Let the volume of air in a cylinder, initially, be V litres.

In each stroke, the vacuum pump removes 1/4th of air remaining in the cylinder at a time. Or we can say, after every stroke, 1-1/4 = 3/4th part of air will remain.

Therefore, volumes will be V, 3V/4 , (3V/4)² , (3V/4)³…and so on

Clearly, we can see here, the adjacent terms of this series do not have the common difference between them.

Therefore, this series is not an A.P.

This is the correct answer.

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