Question

Charge 2Q and Q are placed as shown in figure.
The point at which electric field intensity is zero will
be somewhere
-Q
+20
(1) Between-Q and 2Q
(2) On the left of-Q
(3) On the right of 2Q
(4) On the perpendicular bisector of line joining the
charges​

Answer 1

Answer:

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R.E.F image

Solution It will be left to -Q as there 

the direction of electric failed due 

to -Q and  2Q  are opposite and 

the separation due Q is letter then 

that of 2Q as to equalize the

magnitude of fields.