charge each of +3micro coulomb at placed at three corners of a square whose diagonal is 6 cm long .Electric field intensity at the point of intersection is
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Answer:
3×10*7 N/C
Explanation:
Suppose 3 charges r positive nd one as negative then one negative nd one positive cancels each other therefore we got 2 positive repelling each other by same force nd thus we have to find out by only one charge .
E=Kq/r*2
E = 9×10*9 × 3×10*-6 / 0.03*2
E = 3×10*7 N/C
r is taken as half of diagonal as point of intensity is at the centre of square .
Hope u got ur answer
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