Question

Charge is 2micro coulomb and the distance from large charge sheet is 2 cm. What is the force

Answer 1

Answer:

q1 = 2 micro coulomb = 2 × 10 ^ (-6) C

Similarly q2 = 2 × 10^(-6) C

r = 2cm

r^2 = 4 cm^2 = 4 × 10^(-4) m

k = 9 × 10^9

Now

we know that : -

$f \: = \: \frac{k \: \times \: q1 \: \times q2}{{r}^{2} }$

$f \: = \frac{9 \times {10}^{9} \times 2 \times {10}^{ - 6} \times 2 \times {10}^{ - 6} }{4 \times {10}^{ - 4} }$

$f \: \: = \frac{9 \times {10}^{9} \times 4 \times {10}^{ - 12} }{4 \times {10}^{ - 4} }$

$f \: = 9 \times {10}^{9} \times {10}^{ - 12} \times {10}^{4} \\ \\ f \: = 9 \times {10}^{13} \times {10}^{ - 12}$

$f \: = 9 \times 10 = 90$

Therefore ,

F = 90 N ............is the required answer.