Question

Charge is given as q= (3t^2 +2t +6 ) then find current at 2 sec ?

Answer 1

Answer:

22c

Explanation:

Given,

I=3t2+2t+5

Time interval   t=0  and  t=2s

We know that,

I=dtdq

So, the change       ∫dq=∫02Idt

q=∫02(3t2+2t+5)dt=[t3+t2+5t]02=(8+4+10)=22C

Answer 2

Answer:

$\large \green{ \underline{ \sf \: Given : - }}$

$\sf \: Equation \: of \: a \: charge (q)= 3 {t}^{2} + 2t + 6$

$\large \green{ \underline{ \sf \: To \: find : - }}$

$\sf \: Current \: \: at \: \: 2 \: second$

$\large \green{ \underline{ \sf \:Solution : - }}$

$\sf \: Current (I) = \frac{q}{t}$

$\sf \: \: \: I = \frac{3 {t}^{2} + 2t + 6}{t}$

$\sf \: I = 3t + 2 - \frac{6}{t}$

$: \implies \sf \: at \: \: \: t = 2 \: ec$

$\sf \: I = 3(2) + 2 - \frac{6}{2}$

$\sf \: I = 6 + 2 - 3$

$\sf \: I = 5 \: A$