Question

charge of 7 microcoulomb is placed at the centre of two concentric circles with radius 2 centimetre and 4 centimetre. the ratio of flux through they will be​

Answer 1

Answer:

A force of attraction that holds atoms of a molecule together.

2. The number of hydrogen atoms that can combine with or replace one atom of the element.

3. An atom or molecule with a net electric charge due to the loss or gain of one or more electrons.

Explanation:

Answer 2

The ratio of flux through them will be 1:1

Explanation:

Charge=q=$7\mu C=7\times 10^{-6} C$

$1\mu C=10^{-6} C$

Radius of inner circle=$r_1=2 cm$

Radius of outer circle=$r_2=4 cm$

Gauss' s law

Flux=$\phi=\frac{q}{\epsilon_0}$

Where q=Charge enclose by closed surface

By Gauss' law

Flux passing through the inner circle=$\phi_1=\frac{7\times 10^{-6}}{\epsilon_0}$

Flux passing through the outer circle=$\phi_2=\frac{7\times 10^{-6}}{\epsilon_0}$

Ratio =$\frac{\phi_1}{\phi_2}=\frac{\frac{7\times 10^{-6}}{\epsilon_0}}{\frac{7\times 10^{-6}}{\epsilon_0}}$

$\frac{\phi_1}{\phi_2}=\frac{7\times 10^{-6}}{\epsilon_0}\times \frac{\epsilon_0}{7\times 10^{-6}}$

$\frac{\phi_1}{\phi_2}=\frac{1}{1}$

$\phi_1:\phi_2=1:1$

The ratio of flux through them will be 1:1

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