charge of 9micro coloumb is placed at origin find potential difference between the points (√3, √3) and (3, 0)?
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Answer:
The potential difference b/w the two points is 6.06 volts.
Explanation:
Distance b/w the origin (0,0) and (√3,√3) = √(3+3) = √6 units.
The distance between the origin (0,0) and (3,0) = 3 units.
Potential at (√3,√3) due to the charge = KQ/r (9*10⁹*9*10-⁶)/√6 = 33.06*10³ Volts
Potential at (3,0) due to the charge = KQ/r (9*10⁹*9*10-⁶)/3 = 27*10³ Volts
Thus, the potential difference b/w the two points is = (33.06*10³ - 27*10³) = 6.06 volts.
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