Question

charge of magnitude 2Q and -Q are located at points(a,0,0) and (4a,0,0). find the ratio of flux of electric field due to these charge through concentric sphere a of radius 2a and 8a centered at origin.

Answer 1

Answer:

Explanation:

the total flux through a surface = charge enclosed / ε₀

here the first sphere ( 2a ) encloses only the charge 2Q which is inside it.

so flux₁ = 2Q / ε₀

2nd sphere encloses both the charges. So net charge = 2Q + -Q = Q

so flux₂ = Q / ε₀

So ratio of flux = flux₁ / flux₂ = 2 : 1