Question

charge of mass ‘m’ and charge ‘q’ is accelerated from rest in a uniform electric field of strength ‘E’. The velocity acquired by it two second after released will be ​

Answer 1

Answer:

2qe/m

Explanation:

ina a uniform electric field F=qE

ma =qE so a= qE/m

as u=o hence v=at v=2qe/m (t=2s)