Question

"Charge on electron= 1.6022x10^-19C or 4.8x10^-10 é.s.u"
Question:-)
What does e.s.u means here(explaination? Don't spam...( no coppy)
Ans in your own words if u cant ans pls leave it..

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Answer 1

$\:\:\:\: \: \: \: \: \: \: \: \: \: \: \large\mathfrak{\underline{\underline{\huge\mathcal{\bf{\boxed{\huge\mathcal{!!ANSWER!!}}}}}}}$

$1e = - 1.6 \times 10 {}^{ - 19} c = 4.8 \times 10 { }^{ - 10} esu$

$\:\: \underline{\underline{\bf{\large\mathfrak{~~Explanation~~}}}}$

FROM COULOMB'S LAW

THE force of attraction between two charge particles q1 and q2......is....

$f = \frac{1}{4\pi \: eo} \times \frac{q1 \times q2}{r {}^{2} }$

NOW IN CGS SYSTEM

$eo = \frac{1}{4\pi}$

so..

$f = \frac{q1 \times q2}{r {}^{2} }$

now...in cgs system the unit of charge is esu

(e.s.u=Electrostatic unit)

what is 1 esu charge?

logic:f=1 dyn,q1=q2=q(let);r=1cm...

then ,,q=+-1

ans:

if two point charges are placed at 1cm distance from each other,and if the force between them is 1 dyn .then the point charge will be called 1 esu charge.

1esu=1 statC(stat coulomb)

FOR SI SYSTEM

$f = \frac{1}{4\pi \: eo} \times \frac{q1 \times q2}{r {}^{2} }$

now if ...f=1 N;q1=q2=q(let)...r=1m..then...

q=+-1 Coulomb

What is 1C charge??

ans

if two point charges are placed at 1m distance from each other,and if the force between them is 1 N .then the point charge will be called 1 Coff course charge.

1C=3×10^9 esu.....

therefore....

$1e = 1.6 \times 10 {}^{ - 19} c = 4.8 \times 10 {}^{ - 10} esu$

$\huge\mathcal\green{\underline{hope\:\: this\:\: helps\:\: you}}$

Answer 2

Little knowledge iske pyaar me mat mar