Question

charge Q is placed at each of the two opposite corner of a square a charge Q is placed at the other to corner resultant force on q is zero then what is the relation between Q and q​

Answer 1

Explanation:

By what seems there are only 2 charges thus E.Q=0

either charge on Q is 0 or

electric field is 0

which happens when q is 0 thus

Q/q=0 OR infinity

hope this helps ✌️✌️✌️

Answer 2

Explanation :

Fnetonq=F→1+F→2+F→3Fnetonq=F→1+F→2+F→3

0=Fi^+Fj^+F→30=Fi^+Fj^+F→3

0=kqQa2(i^+j^)+kq2(2–√a)2i^+j^2–√0=kqQa2(i^+j^)+kq2(2a)2i^+j^2

0=(kqQa2+kqQ22–√a2)(i^+j^)0=(kqQa2+kqQ22a2)(i^+j^)