Question

Charge q of mass m revolves around a point charge q due to electrostatic attraction

Answer 1

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Question ⇒  Charge q of mass m revolves around a point charge q due to electrostatic attraction. Find the velocity of the charge, if at each instant distance between the both charge is r.

Solution ⇒

The Electrostatic force of attraction will be balanced by the centripetal force.

Therefore,

 $F_C = F_E$

$\frac{mv&2}{r} = \frac{kq^2}{r^2}$

∴ mv² = kq²/r

∴ v² = kq²/mr

∴ $v = \sqrt{\frac{kq^2}{mr} }$

Hence, the velocity of the charge particle is given by  $v = \sqrt{\frac{kq^2}{mr} }$

Hope it helps.

Answer 2

Answer:

The Electrostatic force of attraction will be balanced by the centripetal force.

Therefore,

 

∴ mv² = kq²/r

∴ v² = kq²/mr