Chemistry, asked by shweta49165, 11 months ago

charge required to liberate 11.5gm of Na is...

Answers

Answered by harsharock17

4

Answer:

0.5 Faraday

Explanation:

Na+e- = Na

charge (inF)=moles of e ?

used=moles of Na deposited

=11.5/23 gm

=0.5 Faraday

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