Charge stored by the 1.5 μF capacitor in the steady state circuit shown is _____ µC.

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Answer:
In steady state,
i=
3
1
A
∴V
A
+1+
3
1
×1=V
B
⇒V
B
−V
A
=
3
4
∴Q=(V
B
−V
A
)×3
=
3
4
×3μc
=4μc
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