Physics, asked by rushikeshphatak04, 1 month ago

Charge stored by the 1.5 μF capacitor in the steady state circuit shown is _____ µC.
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Answers

Answered by 9856183008
0

Answer:

In steady state,

i=

3

1

A

∴V

A

+1+

3

1

×1=V

B

⇒V

B

−V

A

=

3

4

∴Q=(V

B

−V

A

)×3

=

3

4

×3μc

=4μc

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