charge through cross section of conductor is given by Q=5t2_ 2t coulumb . find average current through the conductor in time interval t1=2 t2=4 sec.
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Q(t) = 5t² - 2t
We have to find out current in time interval 2 to 4 sec
So, use formula , i = [Q(t₂) - Q(t₁) ]/(t₂ - t₁)
Q(t₂) = Q(4) = 5(4)² - 2(4) = 80 - 8 = 72
Q(t₁) = Q(2) = 5(2)² - 2(2) = 20 - 4 = 16
so, current , i = (72 - 16)/(4 - 2) = 56/2 = 28 Ampere .
Hence, current through the conductor in 2 to 4 sec is 28 Ampere
We have to find out current in time interval 2 to 4 sec
So, use formula , i = [Q(t₂) - Q(t₁) ]/(t₂ - t₁)
Q(t₂) = Q(4) = 5(4)² - 2(4) = 80 - 8 = 72
Q(t₁) = Q(2) = 5(2)² - 2(2) = 20 - 4 = 16
so, current , i = (72 - 16)/(4 - 2) = 56/2 = 28 Ampere .
Hence, current through the conductor in 2 to 4 sec is 28 Ampere
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