Question

charged particle has a drift velocity 8.4×10⁻⁴ms⁻¹ in electric field of 2.1×10⁻¹⁰Vm⁻¹. Its mobility​

Answer 1

Answer:

4*10^6m/sec

Explanation:

given

vd=8.4*10^-4m/sec

E=2.1*10^-10v/m

since, we know that

mobility=vd/E

mobility=8.4*10^-4/2.1*10^-10

mobility=4*10^-4*10^10

mobilty=4*10^6m/sec