Question

charged particle of charge 2 microcoulomb and mass 10 milligram moving with a velocity of 2000 metre per second and the uniform electric field of strength and cube Newton per coulomb directed perpendicular to its direction find the velocity and displacement of the particle after 10 second​

Answer 1

Answer:The component of velocity perpendicualr to the direction of electric field will remain constant since the particle does not accelerate in that direction.

Hencev_{perpendicular}=1000m/s \implies s_{perpendicular}=v_{perpendicular}t=10000m

The acceleration of particle in direction of electric field=\dfrac{qE}{m}=\dfrac{2\times 10^{-6}\times 10^3}{0.01}m/s^2=0.2m/s^2

Hence the velocity of particle parallel to electric field,v_{parallel}=at=2m/s

\implies s_{parallel}=\dfrac{1}{2}at^2=10m

Explanation: